MATH SOLVE

2 months ago

Q:
# In the circle AB=19, BC=10, and CD=5. The diagram is not drawn to scale.What is the value of xx=23x=53x=38x=58

Accepted Solution

A:

we know that

If two secant segments are drawn to a circle from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.

so

BC*AC=CD*(x+CD)

AB=19

BC=10

CD=5

AC=AB+BC----> AC=29

(x+CD)=BC*AC/CD-----> 10*29/5-----> 58

(x+CD)=58------> x=58-CD-----> x=58-5----> x=53

If two secant segments are drawn to a circle from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.

so

BC*AC=CD*(x+CD)

AB=19

BC=10

CD=5

AC=AB+BC----> AC=29

(x+CD)=BC*AC/CD-----> 10*29/5-----> 58

(x+CD)=58------> x=58-CD-----> x=58-5----> x=53